International Doctorate in Civil and Environmental Engineering
Anisotropic Structures - Theory and Design
Strutture anisotrope: teoria e progetto Paolo VANNUCCI
Lesson 1 - April 2, 2019 - DICEA - Universit´ a di Firenze 1 / 77
Anisotropic Structures - Theory and Design Strutture anisotrope: - - PowerPoint PPT Presentation
International Doctorate in Civil and Environmental Engineering Anisotropic Structures - Theory and Design Strutture anisotrope: teoria e progetto Paolo VANNUCCI Lesson 1 - April 2, 2019 - DICEA - Universit a di Firenze 1 / 77 Topics of the
International Doctorate in Civil and Environmental Engineering
Strutture anisotrope: teoria e progetto Paolo VANNUCCI
Lesson 1 - April 2, 2019 - DICEA - Universit´ a di Firenze 1 / 77
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Figure: Some examples of anisotropic materials or structures.
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1∀a, b, c ∈ V, the dyad (a ⊗ b) is the second-rank tensor defined by the
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Figure: Geometrical elements of a unit cell.
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훼, 훽, 훾 ≠ 90° 훼 훽 훾 훼 훽 훾 훼, 훾=90°, 훽 ≠ 90° 훽 훼, 훾=90°, 훽 ≠ 90° 훾 훼 a a c a ≠ c a b c a ≠ b ≠ c c a ≠ b ≠ c b a Triclinic Monoclinic Monoclinic base- Orthorombic Orthorombic base- primitive centered primitive centered b c a ≠ b ≠ c a c a ≠ b ≠ c b a a ≠ c a a c a a 훾 훾=120° Orthorhombic body- Orthorhombic face- Tetragonal Tetragonal body- Trigonal centered centered primitive centered c c a a a a a a a a a a Hexagonal Cubic Cubic body- Cubic face- primitive centered centered
Figure: The 14 Bravais cells
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Classification Syngony Symmetry elements Examples Voigt Sch H-M N Triclinic none H3BO3, K2Cr2O7, 1 S2 1 21 CuSO4 · 5H2O 2 C1 1 21 Monoclinic a 2-fold a-s or a-a-s Na2SO4 · 10H2O 3 Ch
2
2/m 13 4 S m 13 5 C2 2 13 Orthorhombic 3 mutually orthogonal KNO3, BaSO4 6 Vh mmm 9 7 V 222 9 2-fold a-s or a-a-s 8 Cv
2
mm2 9 Trigonal a 3-fold a-s or a-a-s HgS, CaCO3 9 Su
6
3m 6 10 D3 32 6 11 Cv
3
3m 6 12 S6 3 7 13 C3 3 7 Tetragonal a 4-fold a-s or a-a-s CaSO4, TiO2 14 Dh
4
4/mmm 6 15 D4 4222 6 16 Cv
4
4mm 6 17 Ch
4
4/m 7 18 C4 4 7 19 Su
4
42m 6 20 S4 4 7 Hexagonal a 6-fold a-s or a-a-s CdS, ZnO, graphite 21 Dh
6
6/mmm 5 22 Cv
6
6mm 5 23 D6 622 5 24 Ch
6
6/m 5 25 C6 6 5 26 Dh
3
6m2 5 27 Ch
3
6 5 Cubic 28 Oh m3m 3 four 3-fold a-s arranged as 29 O 432 3 NaCl, Cu, Zinc Blende 30 Td 43m 3 the cubic diagonal 31 Th m3 3 32 T 332 3 Note: Sch= Schoenflies, H-M= Hermann-Mauguin; a-s= axis of symmetry, a-a-s: axis of alternate sym-
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∂xj
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∂t2 = o everywhere → equilibrium equation.
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2Namely, we have used the identity div(L⊤v) = divL · v + L · ∇v, and the
fact that L · ∇v+∇v⊤
2
= L · ∇v ∀L = L⊤
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A
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S11 = Z1111 S12 = Z1122 S13 = Z1133 S14 = 2Z1123 S15 = 2Z1131 S16 = 2Z1112 S22 = Z2222 S23 = Z2233 S24 = 2Z2223 S25 = 2Z2231 S26 = 2Z2212 S33 = Z3333 S34 = 2Z3323 S35 = 2Z3331 S36 = 2Z3312 S44 = 4Z2323 S45 = 4Z2331 S46 = 4Z2312 sym S55 = 4Z3131 S56 = 4Z3112 S66 = 4Z1212
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Figure: Anisotropic stretched cube.
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couplings extension strains- shear stresses
Chentsov’s effect
direct effect of shear stresses direct effect of normal stresses Poisson’s effect
.
6 5 4 3 2 1 66 56 46 36 26 16 56 55 45 35 25 15 46 45 44 34 24 14 36 35 34 33 23 13 26 25 24 23 22 12 16 15 14 13 12 11 6 5 4 3 2 1
! ! ! " ! ! ! # $ ! ! ! % ! ! ! & ' ( ( ( ( ( ( ( ) * + + + + + + + ,
! ! ! " ! ! ! # $ ! ! ! % ! ! ! & ' σ σ σ σ σ σ S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S ε ε ε ε ε ε Figure: Partition of the compliance matrix by mechanical effects.
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1, e′ 2, e′ 3} and let us suppose that these two bases are
i
i = U⊤ei;
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1
2
3
1
2
3
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i = Upq(e′ p ⊗ e′ q)e′ i = Upqδqie′ p = Upie′ p,
k
k = Ukiwi;
m ⊗ Unje′ n =
m ⊗ e′ n
mn = UmiUnjLij;
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m ⊗ Unje′ n ⊗ Upke′ p ⊗ Uqle′ q =
m ⊗ e′ n ⊗ e′ p ⊗ e′ q
mnpq = UmiUnjUpkUqlEijkl.
3∀ A, B and L ∈Lin, A ⊗ B is the 4th-rank tensor defined by
(A ⊗ B)L := (B · L)A. Applying this rule to the dyads of a basis, we get : (ei ⊗ ej ⊗ ek ⊗ el)(ep ⊗ eq) = (ek ⊗ el) · (ep ⊗ eq)(ei ⊗ ej) = δkpδlq(ei ⊗ ej).
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4We will indicate by V the translations vector space, associated with the
and by Lin that of fourth-rank tensors on Lin.
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ijkl = Aklij,
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U2
11
U2
12
U2
13
√ 2U12U13 √ 2U13U11 √ 2U11U12 U2
21
U2
22
U2
23
√ 2U22U23 √ 2U23U21 √ 2U21U22 U2
31
U2
32
U2
33
√ 2U32U33 √ 2U33U31 √ 2U31U32 √ 2U21U31 √ 2U22U32 √ 2U23U33 U23U32 + U22U33 U33U21 + U31U23 U31U22 + U32U21 √ 2U31U11 √ 2U32U12 √ 2U33U13 U32U13 + U33U12 U31U13 + U33U11 U31U12 + U32U11 √ 2U11U21 √ 2U12U22 √ 2U13U23 U12U23 + U13U22 U11U23 + U13U21 U11U22 + U12U21
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