Geometry of the conjugacy problem Andrew Sale Vanderbilt University - - PowerPoint PPT Presentation

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Geometry of the conjugacy problem Andrew Sale Vanderbilt University - - PowerPoint PPT Presentation

Geometry of the conjugacy problem Andrew Sale Vanderbilt University May 14, 2015 Andrew Sale Geometry of the conjugacy problem For a group G , we define two functions: Andrew Sale Geometry of the conjugacy problem For a group G , we define


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Geometry of the conjugacy problem

Andrew Sale

Vanderbilt University

May 14, 2015

Andrew Sale Geometry of the conjugacy problem

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For a group G, we define two functions:

Andrew Sale Geometry of the conjugacy problem

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For a group G, we define two functions:

1 Conjugacy length function

Bounds length of short conjugators.

Andrew Sale Geometry of the conjugacy problem

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For a group G, we define two functions:

1 Conjugacy length function

Bounds length of short conjugators.

2 Permutation conjugacy length function

Inspired by fast solutions to the conjugacy problem in hyerbolic and relatively hyperbolic groups (Bridson–Howie, Epstein–Holt, Bumagin).

Andrew Sale Geometry of the conjugacy problem

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Conjugacy Length Function

G group with length function |·| : G → [0, ∞)

(e.g. word length if finitely generated).

Andrew Sale Geometry of the conjugacy problem

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Conjugacy Length Function

G group with length function |·| : G → [0, ∞)

(e.g. word length if finitely generated).

Definition (Conjugacy length function) CLFG : [0, ∞) → [0, ∞) minimal function satisfying:

Andrew Sale Geometry of the conjugacy problem

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Conjugacy Length Function

G group with length function |·| : G → [0, ∞)

(e.g. word length if finitely generated).

Definition (Conjugacy length function) CLFG : [0, ∞) → [0, ∞) minimal function satisfying: For x ≥ 0, u, v ∈ G such that |u| + |v| ≤ x, then

Andrew Sale Geometry of the conjugacy problem

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Conjugacy Length Function

G group with length function |·| : G → [0, ∞)

(e.g. word length if finitely generated).

Definition (Conjugacy length function) CLFG : [0, ∞) → [0, ∞) minimal function satisfying: For x ≥ 0, u, v ∈ G such that |u| + |v| ≤ x, then u is conjugate to v ⇐ ⇒ ∃ g ∈ G such that (i) gug−1 = v and

Andrew Sale Geometry of the conjugacy problem

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Conjugacy Length Function

G group with length function |·| : G → [0, ∞)

(e.g. word length if finitely generated).

Definition (Conjugacy length function) CLFG : [0, ∞) → [0, ∞) minimal function satisfying: For x ≥ 0, u, v ∈ G such that |u| + |v| ≤ x, then u is conjugate to v ⇐ ⇒ ∃ g ∈ G such that (i) gug−1 = v and (ii) |g| ≤ CLFG(x).

Andrew Sale Geometry of the conjugacy problem

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Conjugacy Length Function

G group with length function |·| : G → [0, ∞)

(e.g. word length if finitely generated).

Definition (Conjugacy length function) CLFG : [0, ∞) → [0, ∞) minimal function satisfying: For x ≥ 0, u, v ∈ G such that |u| + |v| ≤ x, then u is conjugate to v ⇐ ⇒ ∃ g ∈ G such that (i) gug−1 = v and (ii) |g| ≤ CLFG(x). Lemma Γ finitely generated with solvable WP, |·| word length. Then: Conjugacy problem is solvable ⇐ ⇒ CLFΓ is recursive.

Andrew Sale Geometry of the conjugacy problem

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Example: free groups

F free group, finite generating set X. u, v reduced words on X ∪ X−1. e.g. u = aabbbaba−1 v = babababba−1b−1

Andrew Sale Geometry of the conjugacy problem

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Example: free groups

F free group, finite generating set X. u, v reduced words on X ∪ X−1. e.g. u = aabbbaba−1 v = babababba−1b−1 Algorithm to solve conjugacy problem

Andrew Sale Geometry of the conjugacy problem

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Example: free groups

F free group, finite generating set X. u, v reduced words on X ∪ X−1. e.g. u = aabbbaba−1 v = babababba−1b−1 Algorithm to solve conjugacy problem (i) Cyclically reduce u, v to u′, v′, (i) u′ = a−1ua = ab3ab v′ = (ba)−1vba = babab2

Andrew Sale Geometry of the conjugacy problem

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Example: free groups

F free group, finite generating set X. u, v reduced words on X ∪ X−1. e.g. u = aabbbaba−1 v = babababba−1b−1 Algorithm to solve conjugacy problem (i) Cyclically reduce u, v to u′, v′, (i) u′ = a−1ua = ab3ab v′ = (ba)−1vba = babab2 (ii) Cyclically conjugate u′ to v′. (ii) v′ = babu′(bab)−1

Andrew Sale Geometry of the conjugacy problem

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Example: free groups

F free group, finite generating set X. u, v reduced words on X ∪ X−1. e.g. u = aabbbaba−1 v = babababba−1b−1 Algorithm to solve conjugacy problem (i) Cyclically reduce u, v to u′, v′, (i) u′ = a−1ua = ab3ab v′ = (ba)−1vba = babab2 (ii) Cyclically conjugate u′ to v′. (ii) v′ = babu′(bab)−1 The conjugator will be a product

  • f subwords of u and v. Hence

CLFF (x) ≤ x. g = bababa−1 v = gug−1

Andrew Sale Geometry of the conjugacy problem

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State of the art

Known results include: Class of groups CLF(x) Hyperbolic groups linear Lysenok CAT(0) & biautomatic groups exp(x) Bridson–Haefliger RAAGs & special subgroups linear Crisp–Godelle–Wiest Mapping class groups linear Masur–Minsky; Behrstock–Drut ¸u; J. Tao. 2-Step Nilpotent quadratic Ji–Ogle–Ramsey π1(M), M prime 3–manifold x2 Behrstock–Drut ¸u, S Free solvable groups x3 S Plus: wreath products (S), group extensions (S), relatively hyperbolic groups (Ji–Ogle–Ramsey, Z. O’Conner, Bumagin).

Andrew Sale Geometry of the conjugacy problem

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Permutation conjugacy length function, j/w Y. Antol´ ın.

G group, X (finite) generating set, |·| word length. Definition (Permutation conjugacy length function) PCLG,X : N → N minimal function satisfying:

Andrew Sale Geometry of the conjugacy problem

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Permutation conjugacy length function, j/w Y. Antol´ ın.

G group, X (finite) generating set, |·| word length. Definition (Permutation conjugacy length function) PCLG,X : N → N minimal function satisfying: For geodesic words u, v on X such that |u| + |v| ≤ n, then u, v represent conjugate elements of G iff

Andrew Sale Geometry of the conjugacy problem

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Permutation conjugacy length function, j/w Y. Antol´ ın.

G group, X (finite) generating set, |·| word length. Definition (Permutation conjugacy length function) PCLG,X : N → N minimal function satisfying: For geodesic words u, v on X such that |u| + |v| ≤ n, then u, v represent conjugate elements of G iff ∃ cyclic permutations u′, v′ of u, v and g ∈ G such that (i) gu′g−1 = v′ and (ii) |g| ≤ PCLG,X(n).

Andrew Sale Geometry of the conjugacy problem

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Permutation conjugacy length function, j/w Y. Antol´ ın.

G group, X (finite) generating set, |·| word length. Definition (Permutation conjugacy length function) PCLG,X : N → N minimal function satisfying: For geodesic words u, v on X such that |u| + |v| ≤ n, then u, v represent conjugate elements of G iff ∃ cyclic permutations u′, v′ of u, v and g ∈ G such that (i) gu′g−1 = v′ and (ii) |g| ≤ PCLG,X(n). e.g. For a free group PCL = 0.

Andrew Sale Geometry of the conjugacy problem

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Sublinear PCL

Relationship to CLF: PCLG,X(n) ≤ CLFG(n) ≤ PCLG,X(n) + n.

1 w v u u uw = wv CLFG(n) PCLG,X(n)

Andrew Sale Geometry of the conjugacy problem

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Sublinear PCL

Relationship to CLF: PCLG,X(n) ≤ CLFG(n) ≤ PCLG,X(n) + n.

1 w v u u uw = wv CLF(n) PCL(n)

If PCLG,X(n) ≤ K for all n, then conjugacy problem is almost as fast as word problem: (on input geodesic words). Apply the word problem n2 times, on words of length n + 2K, where n is the sum of the length of the input words.

Andrew Sale Geometry of the conjugacy problem

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Relatively hyperbolic groups

Theorem (Antol´ ın–S ’15) Let G be hyperbolic relative to a finite collection of subgroups {Hω}ω∈Ω. There exists a finite generating set X such that X ∩ Hω = Hω and PCLG,X(n) max

ω∈Ω

  • PCLHω,X∩Hω(n)
  • .

Andrew Sale Geometry of the conjugacy problem

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Relatively hyperbolic groups

Theorem (Antol´ ın–S ’15) Let G be hyperbolic relative to a finite collection of subgroups {Hω}ω∈Ω. There exists a finite generating set X such that X ∩ Hω = Hω and PCLG,X(n) max

ω∈Ω

  • PCLHω,X∩Hω(n)
  • .

In particular, hyperbolic groups and groups that are hyperbolic relative to abelian groups will all have PCL bounded by a constant.

Andrew Sale Geometry of the conjugacy problem

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Consequences of constant PCL

Suppose PCLG,X(n) ≤ K.

1 Potentially fast algorithm to solve the conjugacy problem. Andrew Sale Geometry of the conjugacy problem

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Consequences of constant PCL

Suppose PCLG,X(n) ≤ K.

1 Potentially fast algorithm to solve the conjugacy problem. 2 Exponential conjugacy growth rate controlled by exponential

growth rate.

Andrew Sale Geometry of the conjugacy problem

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Consequences of constant PCL

Suppose PCLG,X(n) ≤ K.

1 Potentially fast algorithm to solve the conjugacy problem. 2 Exponential conjugacy growth rate controlled by exponential

growth rate.

3 (Ciobanu-Hermiller-Holt-Rees)

ConjGeo(G, X) is a regular language whenever either

Geo(G, X) has a biautomatic structure, (G, X) has falsification by fellow traveller property.

Andrew Sale Geometry of the conjugacy problem

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PCLG,X(n) < K for hyperbolic groups

G hyperbolic. Take u, v geodesic words, conjugate in G. Cyclic permutations u′ = u2u1, v′ = v2v1 and v′w = wu′ with |w|

  • minimal. Let wi be prefix of w.

Andrew Sale Geometry of the conjugacy problem

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PCLG,X(n) < K for hyperbolic groups

G hyperbolic. Take u, v geodesic words, conjugate in G. Cyclic permutations u′ = u2u1, v′ = v2v1 and v′w = wu′ with |w|

  • minimal. Let wi be prefix of w.

Claim: If 4δ < i < |w| − 4δ then d(wi, u′wi) < 8δ. Use that geodesic hexagons are 4δ–thin.

Andrew Sale Geometry of the conjugacy problem

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PCLG,X(n) < K for hyperbolic groups

G hyperbolic. Take u, v geodesic words, conjugate in G. Cyclic permutations u′ = u2u1, v′ = v2v1 and v′w = wu′ with |w|

  • minimal. Let wi be prefix of w.

Claim: If 4δ < i < |w| − 4δ then d(wi, u′wi) < 8δ. Use that geodesic hexagons are 4δ–thin.

1 w v2 v1 wi u′wi > 4δ > 4δ u2 u1 v2 v1 wi u′wi x u′x < 4δ < 4δ u2 u1

Andrew Sale Geometry of the conjugacy problem

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PCLG,X(n) < K for hyperbolic groups, cont.

v2 v1 wi u′wi wj u′wj 1 w u2 u1 u′ wv′ = u′w

Andrew Sale Geometry of the conjugacy problem

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PCLG,X(n) < K for hyperbolic groups, cont.

v2 v1 wi u′wi wj u′wj 1 w u2 u1 u′

If w−1

j v′wj = w−1 i

v′wj then cut middle chunk out of diagram:

  • btains shorter conjugator.

Andrew Sale Geometry of the conjugacy problem

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PCLG,X(n) < K for hyperbolic groups, cont.

v2 v1 wi u′wi wj u′wj 1 w u2 u1 u′

If w−1

j v′wj = w−1 i

v′wj then cut middle chunk out of diagram:

  • btains shorter conjugator.

So w−1

i

v′wi are distinct. = ⇒ |w| ≤ 8δ + BX(8δ). = ⇒ PCLG,X(n) ≤ 8δ + BX(8δ).

Andrew Sale Geometry of the conjugacy problem

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Yago says:

Andrew Sale Geometry of the conjugacy problem

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Yago says: “Please don’t feed the hexagons!!” Thank you for your attention!

Andrew Sale Geometry of the conjugacy problem