Harmonics for Twisted Steenrod Operators. Fran cois Bergeron - PowerPoint PPT Presentation
Harmonics for Twisted Steenrod Operators. Fran cois Bergeron LaCIM, Universit e du Qu ebec ` a Montr eal with: Adriano Garsia and Nolan Wallach FPSAC August 2010 S n -Harmonic Polynomials Solutions of the system ( 1 + . . . +
Harmonics for Twisted Steenrod Operators. Fran¸ cois Bergeron LaCIM, Universit´ e du Qu´ ebec ` a Montr´ eal with: Adriano Garsia and Nolan Wallach FPSAC August 2010
S n -Harmonic Polynomials Solutions of the system ( ∂ 1 + . . . + ∂ n ) f ( x 1 , . . . , x n ) = 0 ( ∂ 2 1 + . . . + ∂ 2 n ) f ( x 1 , . . . , x n ) = 0 . . . ( ∂ n 1 + . . . + ∂ n n ) f ( x 1 , . . . , x n ) = 0 ∂ are said to be S n -harmonic polynomials . Here ∂ i := ∂x i . They can be characterized as all the linear combinations of � ∂ k 1 1 ∂ k 2 2 · · · ∂ k 2 ( x i − x j ) n i<j 2 FPSAC, August 2010
Graded S n -Module The space H S n of harmonic polynomials for the symmetric group is a graded S n -module , i.e.: � H S n ≃ π d ( H S n ) , d ≥ 0 where π d is the linear projection sending polynomials to there degree d homogeneous component. Recall that the group S n acts on polynomials in n variables x = x 1 , x 2 , . . . , x n by permuting variables: σ · x i = x σ ( i ) . 3 FPSAC, August 2010
Graded Irreducible Decomposition From the now classical decomposition Q [ x ] ≃ Q [ x ] S n ⊗ H S n , as graded S n -modules, we get � � � Q [ x ] ≃ e µ V τ , where: ℓ ( µ ) ≤ n λ ⊢ n sh( τ )= λ V τ is some copy of an irreducible representation of S n , of (1) Frobenius characteristic s λ , in the homogeneous component, in H S n , of degree equal to the cocharge , co( τ ), of τ . (2) The indices τ run over the set of standard tableaux of shape λ . (3) Finally, e µ denotes the elementary polynomials in the variables x , considered as linear operator on Q [ x ]. 4 FPSAC, August 2010
Hilbert Series Recall that we have � � n � 1 dim( π d ( Q [ x ])) t d = 1 − t d ≥ 0 and the previous decomposition gives � � n n � � � 1 1 n λ t co( τ ) = 1 − t 1 − t i i =1 λ ⊢ n sh( τ )= λ with n λ equal to the number of standard tableaux of shape λ . Recall that � ( i − 1) λ i . n ( λ ) := i is the smallest possible value for the cocharge of a standard tableaux of shape λ . 5 FPSAC, August 2010
Twisted Steenrod Operators and Associated Harmonics n � q x i ∂ k +1 + ∂ k D k ; q := H n ; q := { f | D k ; q f = 0 , ∀ k ≥ 1 } i i i =1 n � � H x := { f | � � x i ∂ k +1 D k := D k f = 0 , ∀ k ≥ 1 } i i =1 n � � H x := { f | � � x i ∂ k +1 + ( k + 1) ∂ k D k f = 0 , ∀ k ≥ 1 } D k := i i i =1 n � a i ∂ k D k := H n := { f | D k f = 0 , ∀ k ≥ 1 } i i =1 All of these spaces are homogeneous, and we write � � H n ; q ( t ) , H n ( t ) , H n ( t ) , and H n ( t ) , for the respective Hilbert series. 6 FPSAC, August 2010
Conjecture of Hivert-Thi´ ery Conjecture (HT) . The space H n ; q is isomorphic, as a graded S n -module, to the space of S n -harmonic polynomials, for “generic” values of q . In fact H n ; q = { f | D 1; q f = 0 , D 2; q f = 0 } and since [ D k ; q , D j ; q ] = q ( k − j ) D k + j ; q 7 FPSAC, August 2010
General Conjecture For the general operators n � b i x i ∂ 2 D 1 := i + a i ∂ i , and i =1 n � d i x i ∂ 3 i + c i ∂ 2 := D 2 i , i =1 set H n = { f | D 1 f = 0 , and D 2 f = 0 } . Then Conjecture (B) . There is a graded space isomorphism between the space H n and the space of S n -harmonic polynomials, for “generic” values of a i , b i , c i , and d i . 8 FPSAC, August 2010
Dual Point of View For the scalar product on Q [ x ] defined by if , x a = x b , a ! � x a , x b � := 0 otherwise , for two monomials x a and x b (in vector notation), with a ! standing for a 1 ! a 2 ! · · · a n !, we easily check that i ∂ j i f, g � = � f, x j � x k i ∂ k i g � thus we get the dual operators n � q x k +1 D ∗ ∂ i + x k k ; q = i i i =1 9 FPSAC, August 2010
Hit Polynomials Following R. Wood we say that a polynomial is hit , for the operators D ∗ k ; q , if it can be expressed in the form � D ∗ f ( x ) = k ; q g k ( x ) , k ≥ 1 for some polynomials g k . We write C n ; q for the graded quotient of the space of polynomial by the subspace of hit-polynomials for the operators D ∗ k ; q . Likewise, we write � � C n , C n and for the spaces respectively associated to the operators n n � � � � x k +1 x k +1 ∂ i + ( k + 1) x k D ∗ D ∗ k := and k := i . ∂ i , i i i =1 i =1 10 FPSAC, August 2010
Wood’s Conjecture Conjecture (W) . The space � C n contains a copy of the regular representation spanned by the monomials e x x a , 0 ≤ a i < i, with a = ( a 1 , . . . , a n ) , with e x = x 1 x 2 · · · x n . In fact, we will see that the entire space can be described as follows. Conjecture (BGW) . The space � C n affords the basis e y y a , with a = ( a 1 , . . . , a k ) , 0 ≤ a i < i, with e y = y 1 y 2 · · · y k , k varying from 0 to n , and y varying in all k -subsets of x . Clearly the spaces C n ; q , � C n , � C n are respectively isomorphic, as graded S n -modules, to the spaces H n ; q , � H n , � H n . 11 FPSAC, August 2010
Example For the space � C 3 we have the basis 1 , x 1 , x 2 , x 3 , x 1 x 2 , x 1 x 2 2 , x 1 x 3 , x 1 x 2 3 , x 2 x 3 , x 2 x 2 3 , x 1 x 2 x 3 , x 1 x 2 2 x 3 , x 1 x 2 x 2 3 , x 1 x 2 2 x 2 3 , x 1 x 2 x 3 3 , x 1 x 2 2 x 3 3 . Modulo the conjecture, the associated Hilbert series is � n � n � � t k [ k ] t ! . H n ( t ) = k k =0 12 FPSAC, August 2010
Graded Frobenius Characteristic Recall that the graded Frobenius characteristic of an invariant homogeneous subspace � V = V d , d ≥ 0 of Q [ x ] is � � t d 1 χ V d ( σ ) p λ ( σ ) F V ( t ) := n ! d ≥ 0 σ ∈ S n Since the associated operators are symmetric, the spaces H n ; q , � H n , � H n are invariant homogeneous spaces, we have corresponding � � F n ; q ( t ) , F n ( t ) , and F n ( t ) , graded Frobenius characteristics. 13 FPSAC, August 2010
First Results We have the following Theorem ( 1). If q is considered as a formal parameter, then the space H x ; q is isomorphic, as a graded S n -module, to a submodule of the S n -harmonics. Theorem ( 2). Let the Hilbert series of H x ; q be � c d,n t d , H x ; q ( t ) = d ≥ 0 then � � c d,n = [ n ] t ! ∀ d ≤ n. t d , � Theorem ( 3). The space of tilde-harmonics has the direct sum decomposition � � e y � H x = H y . y ⊆ x 14 FPSAC, August 2010
Proof of Theorem 3 Decompose f in Q [ x ] in the form � f = e y f y y ⊆ x with f y in Q [ y ]. Then one checks that f is in � H x if and only if all f y are chosen to lie in � H y , using the operator identity D k e x = e x � � D k . In other words, we get � e y � H y = � H x , y ⊆ x thus finishing the proof. 15 FPSAC, August 2010
Implication for the Frobenius It follows from this proof that the graded Frobenius characteristic of � H a x is given by the symmetric function n � t k � � F a ( t ) = F a ( t ) h n − k . k =0 Here a stands for the characteristic function for selection of some subset of indices for which we set � { f | � H a := D k f = 0 , if a ( k ) = 0 } , and x � { f | � H a := D k f = 0 , if a ( k ) = 0 } . x 16 FPSAC, August 2010
Kernel of D k The Hilbert series of the kernel of n � b i x i ∂ k +1 + a i ∂ k D k := I i is i =1 � � n − 1 1 (1 + t + . . . + t k − 1 ) , 1 − t and we have an explicit description of it. For k = 1, the elements of the kernel take the form � c r ( y r + Ψ 1 ( y r )) , f = r where, setting x = x n , a = a n , b = b n and y = x 1 , . . . , x n − 1 ; we have � ( − 1) m D m x m 1 ( g ) Ψ 1 ( g ) := m ! . [ a ; b ] m m ≥ 1 17 FPSAC, August 2010
One Generic Case We have the following Theorem ( 4). For all choices of a i ’s such that � a k � = 0 , ∀ K ⊆ { 1 , . . . , n } , K � = ∅ , k ∈ K the Hilbert series of the space n � a i ∂ m + j { f | 1 ≤ j ≤ n } , f = 0 , for i i =1 is � m + n � [ n ]! t n t for all m ≥ 0 . 18 FPSAC, August 2010
Proof of Theorem 4 To prove the theorem, we use the fact that Proposition. Polynomials θ 1 ( x ) , θ 2 ( x ) , . . . , θ n ( x ) form a regular sequence in Q [ x ] if and only if the system of equations θ 1 ( x ) = 0 , θ 2 ( x ) = 0 , . . . , θ n ( x ) = 0 has, for x ∈ Q n , the unique solution x 1 = 0 , x 2 = 0 , . . . , x n = 0 . For our case, we formulate this in the format x m +1 x m +1 x m +1 0 . . . a 1 1 2 n x m +2 x m +2 x m +2 0 . . . a 2 1 2 n = . . . . . ... . . . . . . . . . . x m + n x m + n x m + n . . . a n 0 1 2 n 19 FPSAC, August 2010
An Hyperplane Arrangement For the hyperplane arrangement � � � � = 0 , a k K ⊆{ 1 ,...,n } k ∈ K K � = ∅ the number of chambers are 1 , 2 , 6 , 32 , 370 , 11292 , . . . For n = 3 we get 20 FPSAC, August 2010
Diagonal version Conjecture (B) . The space corresponding to the set of common zeros of the operators n � a i ∂ k x i ∂ j y i , i =1 for all k, j ∈ N such that k + j > 0 , is of dimension ( n + 1) n − 1 , whenever we have � a k � = 0 , k ∈ K for all nonempty subsets K of { 1 , . . . , n } . A stronger statement can be made in term of bigraded Hilbert series, and several sets of variables. 21 FPSAC, August 2010
Recommend
More recommend
Explore More Topics
Stay informed with curated content and fresh updates.