Legendre Polynomials Bernd Schr oder logo1 Bernd Schr oder - PowerPoint PPT Presentation
Overview Solving the Legendre Equation Application Legendre Polynomials Bernd Schr oder logo1 Bernd Schr oder Louisiana Tech University, College of Engineering and Science Legendre Polynomials Overview Solving the Legendre Equation
Overview Solving the Legendre Equation Application Legendre Polynomials Bernd Schr¨ oder logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Legendre Polynomials
Overview Solving the Legendre Equation Application Why are Legendre Polynomials Important? logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Legendre Polynomials
Overview Solving the Legendre Equation Application Why are Legendre Polynomials Important? 1. The generalized Legendre equation m 2 � � � 1 − x 2 � y ′′ − 2 xy ′ + λ − y = 0 arises when the 1 − x 2 equation ∆ u = f ( ρ ) u is solved with separation of variables in spherical coordinates. (QM: hydrogen atom!) The � � cos ( φ ) function y describes the polar part of the solution of ∆ u = f ( ρ ) u . logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Legendre Polynomials
Overview Solving the Legendre Equation Application Why are Legendre Polynomials Important? 1. The generalized Legendre equation m 2 � � � 1 − x 2 � y ′′ − 2 xy ′ + λ − y = 0 arises when the 1 − x 2 equation ∆ u = f ( ρ ) u is solved with separation of variables in spherical coordinates. (QM: hydrogen atom!) The � � cos ( φ ) function y describes the polar part of the solution of ∆ u = f ( ρ ) u . � 1 − x 2 � y ′′ − 2 xy ′ + λ y = 0 is the 2. The Legendre equation special case with m = 0, which turns out to be the key to the generalized Legendre equation. logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Legendre Polynomials
Overview Solving the Legendre Equation Application Why are Legendre Polynomials Important? 1. The generalized Legendre equation m 2 � � � 1 − x 2 � y ′′ − 2 xy ′ + λ − y = 0 arises when the 1 − x 2 equation ∆ u = f ( ρ ) u is solved with separation of variables in spherical coordinates. (QM: hydrogen atom!) The � � cos ( φ ) function y describes the polar part of the solution of ∆ u = f ( ρ ) u . � 1 − x 2 � y ′′ − 2 xy ′ + λ y = 0 is the 2. The Legendre equation special case with m = 0, which turns out to be the key to the generalized Legendre equation. 3. The solutions of both equations must be finite on [ − 1 , 1 ] . logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Legendre Polynomials
Overview Solving the Legendre Equation Application Why are Legendre Polynomials Important? 1. The generalized Legendre equation m 2 � � � 1 − x 2 � y ′′ − 2 xy ′ + λ − y = 0 arises when the 1 − x 2 equation ∆ u = f ( ρ ) u is solved with separation of variables in spherical coordinates. (QM: hydrogen atom!) The � � cos ( φ ) function y describes the polar part of the solution of ∆ u = f ( ρ ) u . � 1 − x 2 � y ′′ − 2 xy ′ + λ y = 0 is the 2. The Legendre equation special case with m = 0, which turns out to be the key to the generalized Legendre equation. 3. The solutions of both equations must be finite on [ − 1 , 1 ] . 4. Because 0 is an ordinary point of the equation, it is natural to attempt a series solution. logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Legendre Polynomials
Overview Solving the Legendre Equation Application y ′′ − 2 xy ′ + λ y = 0 1 − x 2 � � Series Solution of logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Legendre Polynomials
Overview Solving the Legendre Equation Application y ′′ − 2 xy ′ + λ y = 0 1 − x 2 � � Series Solution of � 1 − x 2 � y ′′ − 2 xy ′ + λ y = 0 logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Legendre Polynomials
Overview Solving the Legendre Equation Application y ′′ − 2 xy ′ + λ y = 0 1 − x 2 � � Series Solution of � 1 − x 2 � y ′′ − 2 xy ′ + λ y = 0 1 − x 2 � ∞ � c n n ( n − 1 ) x n − 2 ∑ n = 2 logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Legendre Polynomials
Overview Solving the Legendre Equation Application y ′′ − 2 xy ′ + λ y = 0 1 − x 2 � � Series Solution of � 1 − x 2 � y ′′ − 2 xy ′ + λ y = 0 1 − x 2 � ∞ ∞ � c n n ( n − 1 ) x n − 2 − 2 x c n nx n − 1 ∑ ∑ n = 2 n = 1 logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Legendre Polynomials
Overview Solving the Legendre Equation Application y ′′ − 2 xy ′ + λ y = 0 1 − x 2 � � Series Solution of � 1 − x 2 � y ′′ − 2 xy ′ + λ y = 0 1 − x 2 � ∞ ∞ ∞ � c n n ( n − 1 ) x n − 2 − 2 x c n nx n − 1 + λ ∑ ∑ ∑ c n x n n = 2 n = 1 n = 0 logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Legendre Polynomials
Overview Solving the Legendre Equation Application y ′′ − 2 xy ′ + λ y = 0 1 − x 2 � � Series Solution of � 1 − x 2 � y ′′ − 2 xy ′ + λ y = 0 1 − x 2 � ∞ ∞ ∞ � c n n ( n − 1 ) x n − 2 − 2 x c n nx n − 1 + λ ∑ ∑ ∑ c n x n = 0 n = 2 n = 1 n = 0 logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Legendre Polynomials
Overview Solving the Legendre Equation Application y ′′ − 2 xy ′ + λ y = 0 1 − x 2 � � Series Solution of � 1 − x 2 � y ′′ − 2 xy ′ + λ y = 0 1 − x 2 � ∞ ∞ ∞ � c n n ( n − 1 ) x n − 2 − 2 x c n nx n − 1 + λ ∑ ∑ ∑ c n x n = 0 n = 2 n = 1 n = 0 ∞ c n n ( n − 1 ) x n − 2 ∑ n = 2 logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Legendre Polynomials
Overview Solving the Legendre Equation Application y ′′ − 2 xy ′ + λ y = 0 1 − x 2 � � Series Solution of � 1 − x 2 � y ′′ − 2 xy ′ + λ y = 0 1 − x 2 � ∞ ∞ ∞ � c n n ( n − 1 ) x n − 2 − 2 x c n nx n − 1 + λ ∑ ∑ ∑ c n x n = 0 n = 2 n = 1 n = 0 ∞ ∞ c n n ( n − 1 ) x n − 2 − c n n ( n − 1 ) x n ∑ ∑ n = 2 n = 2 logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Legendre Polynomials
Overview Solving the Legendre Equation Application y ′′ − 2 xy ′ + λ y = 0 1 − x 2 � � Series Solution of � 1 − x 2 � y ′′ − 2 xy ′ + λ y = 0 1 − x 2 � ∞ ∞ ∞ � c n n ( n − 1 ) x n − 2 − 2 x c n nx n − 1 + λ ∑ ∑ ∑ c n x n = 0 n = 2 n = 1 n = 0 ∞ ∞ ∞ c n n ( n − 1 ) x n − 2 − c n n ( n − 1 ) x n − 2 c n nx n ∑ ∑ ∑ n = 2 n = 2 n = 1 logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Legendre Polynomials
Overview Solving the Legendre Equation Application y ′′ − 2 xy ′ + λ y = 0 1 − x 2 � � Series Solution of � 1 − x 2 � y ′′ − 2 xy ′ + λ y = 0 1 − x 2 � ∞ ∞ ∞ � c n n ( n − 1 ) x n − 2 − 2 x c n nx n − 1 + λ ∑ ∑ ∑ c n x n = 0 n = 2 n = 1 n = 0 ∞ ∞ ∞ ∞ c n n ( n − 1 ) x n − 2 − c n n ( n − 1 ) x n − 2 c n nx n + λ c n x n ∑ ∑ ∑ ∑ n = 2 n = 2 n = 1 n = 0 logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Legendre Polynomials
Overview Solving the Legendre Equation Application y ′′ − 2 xy ′ + λ y = 0 1 − x 2 � � Series Solution of � 1 − x 2 � y ′′ − 2 xy ′ + λ y = 0 1 − x 2 � ∞ ∞ ∞ � c n n ( n − 1 ) x n − 2 − 2 x c n nx n − 1 + λ ∑ ∑ ∑ c n x n = 0 n = 2 n = 1 n = 0 ∞ ∞ ∞ ∞ λ c n x n = c n n ( n − 1 ) x n − 2 − c n n ( n − 1 ) x n − 2 c n nx n + ∑ ∑ ∑ ∑ 0 n = 2 n = 2 n = 1 n = 0 logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Legendre Polynomials
Overview Solving the Legendre Equation Application y ′′ − 2 xy ′ + λ y = 0 1 − x 2 � � Series Solution of � 1 − x 2 � y ′′ − 2 xy ′ + λ y = 0 1 − x 2 � ∞ ∞ ∞ � c n n ( n − 1 ) x n − 2 − 2 x c n nx n − 1 + λ ∑ ∑ ∑ c n x n = 0 n = 2 n = 1 n = 0 ∞ ∞ ∞ ∞ λ c n x n = c n n ( n − 1 ) x n − 2 − c n n ( n − 1 ) x n − 2 c n nx n + ∑ ∑ ∑ ∑ 0 n = 2 n = 2 n = 1 n = 0 ∞ ∑ c k + 2 ( k + 2 )( k + 1 ) x k k = 0 logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Legendre Polynomials
Overview Solving the Legendre Equation Application y ′′ − 2 xy ′ + λ y = 0 1 − x 2 � � Series Solution of � 1 − x 2 � y ′′ − 2 xy ′ + λ y = 0 1 − x 2 � ∞ ∞ ∞ � c n n ( n − 1 ) x n − 2 − 2 x c n nx n − 1 + λ ∑ ∑ ∑ c n x n = 0 n = 2 n = 1 n = 0 ∞ ∞ ∞ ∞ λ c n x n = c n n ( n − 1 ) x n − 2 − c n n ( n − 1 ) x n − 2 c n nx n + ∑ ∑ ∑ ∑ 0 n = 2 n = 2 n = 1 n = 0 ∞ ∞ ∑ c k + 2 ( k + 2 )( k + 1 ) x k − ∑ c k k ( k − 1 ) x k k = 0 k = 2 logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Legendre Polynomials
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