#9: Cylindrical and Planar
Imagine charge distributed evenly on a long, straight wire.
E • d A
∫
= E • d A
ends
∫
+ E • d A
side
∫
E = λ 2πε0r
Consider a cylindrical Gaussian surface. Electric field must point radially out/in Cylindrical symmetry
E • d A = 0
For the ends of the cylinder For the side of the cylinder
E • d A = EdA ε0 E • d A
∫
= ε0E dA
∫
= ε0E 2πrh
( ) = qenc= λh
23.4-23.5