❍❛r❞♥❡ss ♦❢ ❈♦♠♣✉t✐♥❣ t❤❡ ❇✐❝❧✐q✉❡ P❛rt✐t✐♦♥ ◆✉♠❜❡r
❆❧❡①❛♥❞❡r ❘✳ ❇❧♦❝❦ ❏✉❧② ✶✼✱ ✷✵✶✼
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rss t t q - - PowerPoint PPT Presentation
rss t t q Prtt r r
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◮ ▼✐♥✐♠✉♠ ♥✉♠❜❡r ♦❢ ❜✐❝❧✐q✉❡s ♥❡❡❞❡❞ t♦ ♣❛rt✐t✐♦♥ t❤❡ ❡❞❣❡s ♦❢ ❛
◮ ◆♦t❡ t❤❛t G ❝❛♥ ❜❡ ❛♥② ❣r❛♣❤ ◮ ❇✐❝❧✐q✉❡s ❛r❡ ❝♦♠♣❧❡t❡ ❜✐♣❛rt✐t❡ ❣r❛♣❤s✱ ❞❡♥♦t❡❞ Kn,m ✷ ✴ ✶✻
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◮ ❙❤♦✇❡❞ bp (G) max{n+ (A(G)) , n− (A(G))} ❬❲✐ts❡♥❤❛✉s❡♥✱
◮ ❑♥♦✇♥ t❤❛t n− (A(Kn)) = (n − 1) ◮ ❈❛♥ ♣❛rt✐t✐♦♥ Kn ✐♥t♦ (n − 1) st❛rs ⋆ ❆ st❛r ✐s ❛ ❜✐❝❧✐q✉❡ ♦❢ t❤❡ ❢♦r♠ K1,i ❢♦r s♦♠❡ ♣♦s✐t✐✈❡ ✐♥t❡❣❡r i ✹ ✴ ✶✻
◮ ❆s❦✐♥❣ ❢♦r ✉♥✐q✉❡ i ❛♥❞ r = k = 2 ❛s❦s ❢♦r bp (Kn)
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◮ ❊①❛♠✐♥❡❞ ❜② ◆♦❣❛ ❆❧♦♥ ❬❆❧♦✾✼❪ ◮ ❙❤♦✇❡❞ t❤❛t ✇✐t❤ G = Kn✱ bpt (G) ✐s ❡q✉✐✈❛❧❡♥t t♦ ✜♥❞✐♥❣ t❤❡ ♠❛①
◮ ❆❧s♦ s❤♦✇❡❞ t❤❛t bpt (Kn) Θ
◮ ▼✐♥✐♠✉♠ ✭❛♠♦✉♥t ♦❢✮ ❧❡❛❦❛❣❡ t❤❛t ❦✐❧❧s t❤❡ ♣♦ss✐❜✐❧✐t② ♦❢ ❦❡②
◮ min H(L) s✉❝❤ t❤❛t I(RA, RB|L) = 0 ◮ ❇✐❝❧✐q✉❡s ❛r❡ ✉s❡❧❡ss ❢♦r ❑❆ ✭❜❡❝❛✉s❡ ✵ ♠✉t✉❛❧ ✐♥❢♦r♠❛t✐♦♥✮ ◮ ❘♦✉❣❤❧② ❝♦rr❡s♣♦♥❞s t♦ t❤❡ ❜✐❝❧✐q✉❡ ♣❛rt✐t✐♦♥ ♥✉♠❜❡r
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◮ ▼❛♥② t✐♠❡s✱ ♥❡❛r ♦♣t✐♠❛❧ s♦❧✉t✐♦♥ ✐♥ ♦♥❡ ♣r♦❜❧❡♠ r❡❞✉❝❡s t♦ ❛ ♣♦♦r
◮ ●✐✈❡s ♣r♦♦❢ t❤❛t bp ✐s ◆P✲❍❛r❞ t♦ ❛♣♣r♦①✐♠❛t❡ ❜② ❛ ❝♦♥t✐♥✉♦✉s
◮ ❚❤❡ ♣r♦♦❢ ✐s ♥♦t ✈❡r② ✐♥s✐❣❤t❢✉❧✱ s♦ ✐t ✇✐❧❧ ❜❡ s❦✐♣♣❡❞ ✐♥ t❤✐s t❛❧❦ ✶✵ ✴ ✶✻
◮ ❈❤♦♦s❡ ♣❛r❛♠❡t❡r r ✭t♦ ❜❡ ✜①❡❞ ❧❛t❡r✮ ❛♥❞ ♣❛rt✐t✐♦♥ L ✐♥t♦ n/r
◮ ❋♦r ❡❛❝❤ Li✱ r✉♥ ❛♥ α(r)✲❛♣♣r♦①✐♠❛t✐♦♥ ❛❧❣♦r✐t❤♠ t♦ ✜♥❞ ❛ ❜✐❝❧✐q✉❡
◮ ❊❛❝❤ ❜✐❝❧✐q✉❡ ❢r♦♠ ❡❛❝❤ Li ❛r❡ ♣✉t t♦❣❡t❤❡r ❛♥❞ ❢r♦♠ ❛ ❜✐❝❧✐q✉❡
⋆ ◆♦t❡ t❤❛t s✐♥❝❡ Li ✇❡r❡ ❡❞❣❡✲❞✐s❥♦✐♥t✱ t❤✐s ✐s ❛❧s♦ ❛ ❜✐❝❧✐q✉❡ ♣❛rt✐t✐♦♥ ✶✶ ✴ ✶✻
◮ ●✐✈❡♥ Li✱ r✉♥ ❛ ❜r✉t❡ ❢♦r❝❡ ❛❧❣♦r✐t❤♠ ♦✈❡r ❛❧❧ 2r s✉❜s❡ts ❛♥❞
◮ ❙✉❝❤ ❛ ❞❡✜♥❡❞ s✉❜s❡t S ❛♥❞ ✐ts ✐♥t❡rs❡❝t✐♦♥ ✇✐t❤ t❤❡ s❡t
◮ ❘❡t✉r♥ t❤❡ s♠❛❧❧❡st t✉♣❧❡ ♦❢ ✈❡rt❡① s❡ts ✇❤✐❝❤ ❝♦✈❡rs ❛❧❧ ❡❞❣❡s
◮ ❆♥ ♦♣t✐♠❛❧ s♦❧✉t✐♦♥ ❤❛s ❛t ♠♦st r ❜✐❝❧✐q❡s✱ s♦ t❤✐s r❡t✉r♥s ❛♥
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◮ ❖♥❡ ❡①✐sts ✉s✐♥❣ t❤❡ P✐❣❡♦♥ ❍♦❧❡ Pr✐♥❝✐♣❧❡✱ ❜✉t ✉s❡s str✉❝t✉r❡s ✇✐t❤
◮ ❚❛✐t ❬❚❛✐✶✸❪ ❝❧❛✐♠s ❋✳❘✳❑✳ ❈❤✉♥❣ ❝♦♥✜r♠s t❤❡r❡ ❡①✐sts ❛ ✏❜❡tt❡r✑
◮ ❇❡st ❦♥♦✇♥ ❜♦✉♥❞s ❛r❡
◮ ❊❛s② t♦ ❛s❦✿ ✇❤❛t ✐s bpt (Kn) ❢♦r ❝♦♥st❛♥t t❄ ✶✹ ✴ ✶✻
◮ ❈❤❛❧❡r♠s♦♦❦ ❡t ❛❧✳ ❬❈❍❍❑✶✹❪ ❣✐✈❡ ❜❡tt❡r ❣✉❛r❛♥t❡❡s ✐❢
◮ ❍♦✇ ❣♦♦❞ ♦❢ ❛♥ ❛♣♣r♦①✐♠❛t✐♦♥ ✐s ♦♥❡ t♦ t❤❡ ♦t❤❡r❄
◮ ❑♥♦✇♥ t❤❛t bc bp ◮ ❬P✐♥✶✹❪ ❚❤✐s r❡❧❛t✐♦♥ ♠❛② ❜❡ q✉✐t❡ ❧♦♦s❡✿ ⋆ bp (Kn) 2bc(Kn)−1 − 1 ✭♥♦t❡ t❤❛t bc (Kn) = ⌈log n⌉✮ ⋆ bp (G) 1 2
◮ ❊✈❡♥ ❢♦r ❜✐♣❛rt✐t❡ ❣r❛♣❤s
◮ ❊✈❡♥ ❢♦r ❜✐♣❛rt✐t❡ ❣r❛♣❤s
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