SLIDE 5 From Integrated Correlator to ∆mlat
K
If we insert a complete set of intermediate states, we find: A = N2
KemK (tf ti) X n
hK 0|HW |nihn|HW | ¯ K 0i mK En {T + e(mK En)T 1 mK En } (3) with T ⌘ tb ta + 1. For |ni(in our case |0i, |⇡⇡i, |⌘i, |⇡i) with En < mK or En ⇠ mK: the exponential terms will be significant. We can:
use the freedom of adding cs¯ sd, cp¯ s5d operators to the weak Hamiltonian to remove two of the contributions. Here we choose: h0|HW cp¯ s5d|K 0i = 0, h⌘|HW cs¯ sd|K 0i = 0 subtract contributions from other states(|⇡i, |⇡⇡i) explicitly
Therefore, by fitting the coefficient of T from integrated correlators we can obtain: (4) ∆mlat
K ⌘ 2
X
n
hK 0|HW |nihn|HW | ¯ K 0i mK En
Bigeng Wang (Columbia Univeirsity) Results for KL KS mass difference Lattice 2018 4 / 19