Variation of NronSeveri ranks of reductions of K3 surfaces Edgar - - PowerPoint PPT Presentation

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Variation of NronSeveri ranks of reductions of K3 surfaces Edgar - - PowerPoint PPT Presentation

Variation of NronSeveri ranks of reductions of K3 surfaces Edgar Costa (Massachusetts Institute of Technology) May 28th, 2019 The University of Tenessee Knoxville Presented at 2019 John H. Barrett Memorial Lectures Slides available at


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SLIDE 1

Variation of Néron–Severi ranks of reductions

  • f K3 surfaces

Edgar Costa (Massachusetts Institute of Technology) May 28th, 2019 The University of Tenessee Knoxville

Presented at 2019 John H. Barrett Memorial Lectures Slides available at edgarcosta.org under Research

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SLIDE 2

Elliptic curves

E : y2 = x3 + ax + b, a, b ∈ Z Write Ep := E mod p

  • What can we say about #Ep for an arbitrary p?
  • Given

Ep for many p, what can we say about E? studying the statistical properties Ep.

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SLIDE 3

Elliptic curves

E : y2 = x3 + ax + b, a, b ∈ Z Write Ep := E mod p

  • What can we say about #Ep for an arbitrary p?
  • Given #Ep for many p, what can we say about E?

studying the statistical properties Ep.

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SLIDE 4

Elliptic curves

E : y2 = x3 + ax + b, a, b ∈ Z Write Ep := E mod p

  • What can we say about #Ep for an arbitrary p?
  • Given #Ep for many p, what can we say about E?

⇝ studying the statistical properties #Ep.

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SLIDE 5

Hasse’s bound

Theorem (Hasse) #Ep = p + 1 − ap, ap ∈ [−2√p, 2√p] Alternatively, we could also have written the formula above as ap p 1 Ep

p

2 p 2 p Question What can we say about the error term ap p as p ?

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SLIDE 6

Hasse’s bound

Theorem (Hasse) #Ep = p + 1 − ap, ap ∈ [−2√p, 2√p] Alternatively, we could also have written the formula above as ap := p + 1 − #Ep = Tr Frobp ∈ [−2√p, 2√p] Question What can we say about the error term ap p as p ?

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SLIDE 7

Hasse’s bound

Theorem (Hasse) #Ep = p + 1 − ap, ap ∈ [−2√p, 2√p] Alternatively, we could also have written the formula above as ap := p + 1 − #Ep = Tr Frobp ∈ [−2√p, 2√p] Question What can we say about the error term ap/√p as p → ∞?

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SLIDE 8

Two types of elliptic curves

ap := p + 1 − #Ep = Tr Frobp ∈ [−2√p, 2√p] There are two limiting distributions for ap/√p non-CM CM E E d Over an elliptic curve E is a torus E where

1 2

and we have E

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SLIDE 9

Two types of elliptic curves

ap := p + 1 − #Ep = Tr Frobp ∈ [−2√p, 2√p] There are two limiting distributions for ap/√p non-CM CM E E d

  • 2
  • 1

1 2

  • 2
  • 1

1 2

Over an elliptic curve E is a torus E where

1 2

and we have E

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SLIDE 10

Two types of elliptic curves

ap := p + 1 − #Ep = Tr Frobp ∈ [−2√p, 2√p] There are two limiting distributions for ap/√p non-CM CM EndQ Eal = Q EndQ Eal = Q( √ −d)

  • 2
  • 1

1 2

  • 2
  • 1

1 2

Over an elliptic curve E is a torus E where

1 2

and we have E

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SLIDE 11

Two types of elliptic curves

ap := p + 1 − #Ep = Tr Frobp ∈ [−2√p, 2√p] There are two limiting distributions for ap/√p non-CM CM EndQ Eal = Q EndQ Eal = Q( √ −d)

  • 2
  • 1

1 2

  • 2
  • 1

1 2

Over C an elliptic curve E is a torus EC ≃ C/Λ, where Λ = Zω1 + Zω2 = and we have End Eal = End Λ

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SLIDE 12

How to distinguish between the two types?

non-CM CM EndQ Eal = Q EndQ Eal = Q( √ −d)

  • 2
  • 1

1 2

  • 2
  • 1

1 2

  • EndQ Eal ֒

→ EndQ Eal

p ←

֓ Q(Frobp)

  • ap ̸= 0 ⇐

⇒ EndQ Epal is a quadratic field

  • If E has CM and ap

0, then E Ep .

  • If E is non-CM, then

Ep Eq with prob. 1.

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SLIDE 13

How to distinguish between the two types?

non-CM CM EndQ Eal = Q EndQ Eal = Q( √ −d)

  • 2
  • 1

1 2

  • 2
  • 1

1 2

  • EndQ Eal ֒

→ EndQ Eal

p ←

֓ Q(Frobp)

  • ap ̸= 0 ⇐

⇒ EndQ Epal is a quadratic field

  • If E has CM and ap ̸= 0, then EndQ Eal ≃ EndQ Eal

p .

  • If E is non-CM, then

Ep Eq with prob. 1.

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SLIDE 14

How to distinguish between the two types?

non-CM CM EndQ Eal = Q EndQ Eal = Q( √ −d)

  • 2
  • 1

1 2

  • 2
  • 1

1 2

  • EndQ Eal ֒

→ EndQ Eal

p ←

֓ Q(Frobp)

  • ap ̸= 0 ⇐

⇒ EndQ Epal is a quadratic field

  • If E has CM and ap ̸= 0, then EndQ Eal ≃ EndQ Eal

p .

  • If E is non-CM, then EndQ Eal

p ∩ EndQ Eal q ≃ Q with prob. 1.

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SLIDE 15

Examples

E : y2 + y = x3 − x2 − 10x − 20 (11.a2)

  • EndQ Eal

2 ≃ Q(√−1)

  • EndQ Eal

3 ≃ Q(√−11)

  • ⇒ EndQ Eal = Q

E y2 y x3 7 (27.a2)

  • p

2 3 ap Ep is a Quaternion algebra

  • p

1 3 Ep 3

  • E

3

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SLIDE 16

Examples

E : y2 + y = x3 − x2 − 10x − 20 (11.a2)

  • EndQ Eal

2 ≃ Q(√−1)

  • EndQ Eal

3 ≃ Q(√−11)

  • ⇒ EndQ Eal = Q

E : y2 + y = x3 − 7 (27.a2)

  • p = 2 mod 3 ⇒ ap = 0 ⇒ EndQ Eal

p is a Quaternion algebra

  • p = 1 mod 3 ⇒ EndQ Eal

p ≃ Q(

√ −3)

  • ⇝ EndQ Eal = Q(

√ −3)

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SLIDE 17

K3 surfaces

K3 surfaces are a possible generalization of elliptic curves They may arise in many ways:

  • smooth quartic surfaces in P3

X : f(x, y, z, w) = 0, deg f = 4

  • double cover of P2 branched over a sextic curve

X : w2 = f(x, y, z), deg f = 6 Can we play similar game as before? In this case, instead of studying Xp or

p we study

p Xp 2 4 22

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SLIDE 18

K3 surfaces

K3 surfaces are a possible generalization of elliptic curves They may arise in many ways:

  • smooth quartic surfaces in P3

X : f(x, y, z, w) = 0, deg f = 4

  • double cover of P2 branched over a sextic curve

X : w2 = f(x, y, z), deg f = 6 Can we play similar game as before? In this case, instead of studying Xp or

p we study

p Xp 2 4 22

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SLIDE 19

K3 surfaces

K3 surfaces are a possible generalization of elliptic curves They may arise in many ways:

  • smooth quartic surfaces in P3

X : f(x, y, z, w) = 0, deg f = 4

  • double cover of P2 branched over a sextic curve

X : w2 = f(x, y, z), deg f = 6 Can we play similar game as before? In this case, instead of studying #Xp or Tr Frobp we study p − → rk NS Xpal ∈ {2, 4, . . . , 22}

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SLIDE 20

K3 Surfaces

X/Q a K3 surface p − → rk NS Xpal ∈ {2, 4, . . . , 22} This is analogous to studying: p − → rk End Epal ∈ {2, 4} Recall that:

  • Ep

4 ap

  • ap

1 p

if E is non-CM (Lang–Trotter) 1 2 if E has CM by d In the later case, p ap p p is ramified or inert in d

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SLIDE 21

K3 Surfaces

X/Q a K3 surface p − → rk NS Xpal ∈ {2, 4, . . . , 22} This is analogous to studying: p − → rk End Epal ∈ {2, 4} Recall that:

  • rk End Epal = 4 ⇐

⇒ ap = 0

  • Prob(ap = 0) =

  

?

1 √p

if E is non-CM (Lang–Trotter) 1/2 if E has CM by Q( √ −d) In the later case, p ap p p is ramified or inert in d

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SLIDE 22

K3 Surfaces

X/Q a K3 surface p − → rk NS Xpal ∈ {2, 4, . . . , 22} This is analogous to studying: p − → rk End Epal ∈ {2, 4} Recall that:

  • rk End Epal = 4 ⇐

⇒ ap = 0

  • Prob(ap = 0) =

  

?

1 √p

if E is non-CM (Lang–Trotter) 1/2 if E has CM by Q( √ −d) In the later case, {p : ap = 0} = {p : p is ramified or inert in Q( √ −d)}

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SLIDE 23

Néron–Severi group

  • NS • = Néron–Severi group of • ≃ {curves on •}/ ∼
  • ρ(•) = rk NS •
  • Xp := X mod p

X X X 1 2 20 Xp Xp Xp 2 4 22 Theorem (Charles) For infinitely many p we have Xp

q

Xq .

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SLIDE 24

Néron–Severi group

  • NS • = Néron–Severi group of • ≃ {curves on •}/ ∼
  • ρ(•) = rk NS •
  • Xp := X mod p

X

  • NS Xal
  • ρ(Xal)
  • ???
  • ∈ {1, 2, . . . , 20}

Xp

NS Xpal ρ(Xpal)

∈ {2, 4, . . . 22} Theorem (Charles) For infinitely many p we have Xp

q

Xq .

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SLIDE 25

Néron–Severi group

  • NS • = Néron–Severi group of • ≃ {curves on •}/ ∼
  • ρ(•) = rk NS •
  • Xp := X mod p

X

  • NS Xal
  • ρ(Xal)
  • ???
  • ∈ {1, 2, . . . , 20}

Xp

NS Xpal ρ(Xpal)

∈ {2, 4, . . . 22} Theorem (Charles) For infinitely many p we have ρ(Xpal) = minq ρ(Xqal).

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SLIDE 26

The Problem

X

  • NS Xal
  • ρ(Xal)
  • ???
  • ∈ {1, 2, . . . , 20}

Xp

NS Xpal ρ(Xpal)

∈ {2, 4, . . . 22} Theorem (Charles) For infinitely many p we have ρ(Xpal) = minq ρ(Xqal). What can we say about the following:

  • Πjump(X) :=

{ p : ρ(Xpal) > minq ρ(Xqal) }

  • X B

p B p

jump X

p B as B Let’s do some numerical experiments!

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SLIDE 27

The Problem

X

  • NS Xal
  • ρ(Xal)
  • ???
  • ∈ {1, 2, . . . , 20}

Xp

NS Xpal ρ(Xpal)

∈ {2, 4, . . . 22} Theorem (Charles) For infinitely many p we have ρ(Xpal) = minq ρ(Xqal). What can we say about the following:

  • Πjump(X) :=

{ p : ρ(Xpal) > minq ρ(Xqal) }

  • γ(X, B) := # {p ≤ B : p ∈ Πjump(X)}

# {p ≤ B} as B → ∞ Let’s do some numerical experiments!

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SLIDE 28

The Problem

X

  • NS Xal
  • ρ(Xal)
  • ???
  • ∈ {1, 2, . . . , 20}

Xp

NS Xpal ρ(Xpal)

∈ {2, 4, . . . 22} Theorem (Charles) For infinitely many p we have ρ(Xpal) = minq ρ(Xqal). What can we say about the following:

  • Πjump(X) :=

{ p : ρ(Xpal) > minq ρ(Xqal) }

  • γ(X, B) := # {p ≤ B : p ∈ Πjump(X)}

# {p ≤ B} as B → ∞ Let’s do some numerical experiments!

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SLIDE 29

Two generic K3 surfaces, ρ(Xal) = 1

γ(X, B) ? ∼ cX √ B , B → ∞ p

jump X

1 p Why?

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SLIDE 30

Two generic K3 surfaces, ρ(Xal) = 1

γ(X, B) ? ∼ cX √ B , B → ∞ = ⇒ Prob(p ∈ Πjump(X)) ? ∼ 1/√p Why?

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SLIDE 31

Two generic K3 surfaces, ρ(Xal) = 1

γ(X, B) ? ∼ cX √ B , B → ∞ = ⇒ Prob(p ∈ Πjump(X)) ? ∼ 1/√p Why?

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SLIDE 32

Three K3 surfaces with ρ(Xal) = 2

No obvious trend… Could it be related to some integer being a square modulo p?

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SLIDE 33

Three K3 surfaces with ρ(Xal) = 2

No obvious trend… Could it be related to some integer being a square modulo p?

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SLIDE 34

Three K3 surfaces with ρ(Xal) = 2

No obvious trend… Could it be related to some integer being a square modulo p?

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SLIDE 35

We can explain the 1/2

Theorem (C, C–Elsenhans–Jahnel) If ρ(Xal) = minq ρ(Xpal), then there is a dX ∈ Z such that: { p > 2 : p inert in Q( √ dX) } ⊂ Πjump(X). In general, dX is not a square. Corollary If dX is not a square:

  • B

X B 1 2

  • X

has infinitely many rational curves.

D3 1 5 151 22490817357414371041 387308497430149337233666358807996260780875056740850984213276970343278935342068889706146733313789 D4 53 2624174618795407 512854561846964817139494202072778341 1215218370089028769076718102126921744353362873 6847124397158950456921300435158115445627072734996149041990563857503 D5 1 47 3109 4969 14857095849982608071 445410277660928347762586764331874432202584688016149 658652708525052699993424198738842485998115218667979560362214198830101650254490711

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SLIDE 36

We can explain the 1/2

Theorem (C, C–Elsenhans–Jahnel) If ρ(Xal) = minq ρ(Xpal), then there is a dX ∈ Z such that: { p > 2 : p inert in Q( √ dX) } ⊂ Πjump(X). In general, dX is not a square. Corollary If dX is not a square:

  • lim infB→∞ γ(X, B) ≥ 1/2
  • Xal has infinitely many rational curves.

D3 1 5 151 22490817357414371041 387308497430149337233666358807996260780875056740850984213276970343278935342068889706146733313789 D4 53 2624174618795407 512854561846964817139494202072778341 1215218370089028769076718102126921744353362873 6847124397158950456921300435158115445627072734996149041990563857503 D5 1 47 3109 4969 14857095849982608071 445410277660928347762586764331874432202584688016149 658652708525052699993424198738842485998115218667979560362214198830101650254490711

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SLIDE 37

We can explain the 1/2

Theorem (C, C–Elsenhans–Jahnel) If ρ(Xal) = minq ρ(Xpal), then there is a dX ∈ Z such that: { p > 2 : p inert in Q( √ dX) } ⊂ Πjump(X). In general, dX is not a square. Corollary If dX is not a square:

  • lim infB→∞ γ(X, B) ≥ 1/2
  • Xal has infinitely many rational curves.

D3 = − 1 · 5 · 151 · 22490817357414371041 · 387308497430149337233666358807996260780875056740850984213276970343278935342068889706146733313789 D4 =53 · 2624174618795407 · 512854561846964817139494202072778341 · 1215218370089028769076718102126921744353362873 · 6847124397158950456921300435158115445627072734996149041990563857503 D5 = − 1 · 47 · 3109 · 4969 · 14857095849982608071 · 445410277660928347762586764331874432202584688016149 · 658652708525052699993424198738842485998115218667979560362214198830101650254490711

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SLIDE 38

Experimental data for ρ(Xal) = 2 (again)

What if we ignore { p > 2 : p inert in Q(√dX) } ⊂ Πjump(X)? X

dX

B cX B B Example 3 Example 4 Example 5

γ γ γ

p

jump X

1 if dX is not a square modulo p

1 p

  • therwise

Why?

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SLIDE 39

Experimental data for ρ(Xal) = 2 (again)

What if we ignore { p > 2 : p inert in Q(√dX) } ⊂ Πjump(X)? γ ( XQ (√

dX

), B )

?

∼ cX √ B , B → ∞ Example 3 Example 4 Example 5

γ( )

100 1000 104 105 0.05 0.10 0.50 1

γ( )

1000 104 105 0.05 0.10 0.50 1

γ( )

100 1000 104 105 0.05 0.10 0.50 1

p

jump X

1 if dX is not a square modulo p

1 p

  • therwise

Why?

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SLIDE 40

Experimental data for ρ(Xal) = 2 (again)

What if we ignore { p > 2 : p inert in Q(√dX) } ⊂ Πjump(X)? γ ( XQ (√

dX

), B )

?

∼ cX √ B , B → ∞ Example 3 Example 4 Example 5

γ( )

100 1000 104 105 0.05 0.10 0.50 1

γ( )

1000 104 105 0.05 0.10 0.50 1

γ( )

100 1000 104 105 0.05 0.10 0.50 1

Prob(p ∈ Πjump(X)) =    1 if dX is not a square modulo p

?

1 √p

  • therwise

Why?