Potential Energy and Conservation of Mechanical Energy Conservative - - PDF document

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Potential Energy and Conservation of Mechanical Energy Conservative - - PDF document

Potential Energy and Conservation of Mechanical Energy Conservative and Nonconservative Forces Potential Energy Conservation of Mechanical Energy Homework 1 First Definition of Conservative and Nonconservative Forces A force


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SLIDE 1

Potential Energy and Conservation of Mechanical Energy

  • Conservative and Nonconservative Forces
  • Potential Energy
  • Conservation of Mechanical Energy
  • Homework

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SLIDE 2

First Definition of Conservative and Nonconservative Forces

  • A force is conservative if the kinetic energy of a parti-

cle on which it acts returns to its initial value after any round trip. A force is nonconservative if the kinetic energy changes.

  • An example of a conservative force is the force ex-

erted by a spring

  • An example of a nonconservative force is friction

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SLIDE 3

Second Definition of Conservative and Nonconservative Forces

  • A force is conservative if the work done by the force
  • n a particle that moves through any round trip is
  • zero. A force is nonconservative if the work done by

the force on a particle that moves through any round trip is not zero.

  • First and second definitions are equivalent from the

Work-Energy Theorem (W = ∆K)

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SLIDE 4

Third Definition of Conservative and Nonconservative Forces

  • A force is conservative if the work done by it on a

particle that moves between two points depends only

  • n these points and not on the path followed. A force

is nonconservative if the work done by it on a particle that moves between two points depends on the path taken between these two points.

  • The work done against friction depends on the path

taken since it is a nonconservative force

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SLIDE 5

Potential Energy

  • When conservative forces are acting (e.g. spring force,

gravity) ∆K + ∆U = 0 where U = potential energy (has meaning only for conservative forces)

  • This means that the sum of the kinetic and potential

energies is a constant U + K = a constant

  • From the Work-Energy Theorem

W = ∆K = −∆U

  • For one dimensional motion

∆U = −W = −

xf

xi F(x)dx

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SLIDE 6

Conservation of Mechanical Energy

  • Since the sum of the kinetic and potential energies is

a constant when only conservative forces are acting, we can write Ki + Ui = Kf + Uf

  • We can also calculate the force from the potential en-

ergy function F(x) = −dU(x) dx

  • Check

∆U = −

xf

xi F(x)dx = −

xf

xi

   −dU(x)

dx

    dx

∆U =

xf

xi dU(x)dx = U(xf) − U(xi) = Uf − Ui

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SLIDE 7

Conservation of Mechanical Energy (Cont’d)

Consider a particle moving from A to B along the x-axis with a single conservative force acting on it ∆U = UB − UA UB = ∆U + UA = −

xB

xA F (x) dx + UA

We cannot assign a value to UB until we assign one to

  • UA. Usually we choose UA = 0.

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SLIDE 8

Gravitational Potential Energy

Fg = −mg Ug(y) = −

y

0 Fgdy + Ug(0) = −

y

0 (−mg) dy + Ug(0)

Ug(y) = mgy + Ug(0) Let Ug(0) = 0 ⇒ Ug(y) = mgy Note : Fg = −dUg(y) dy = −d (mgy) dy = −mg

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SLIDE 9

Potential Energy of a Spring

Fs(x) = −kx Us(x) = −

x

0 Fs(x)dx + Us(0) = −

x

0 (−kx) dx + Us(0)

Us(x) = 1 2kx2 + Us(0) Let Us(0) = 0 ⇒ Us(x) = 1 2kx2 Note; Fs(x) = −dUs(x) dx = − d dx

  1

2kx2

   = −kx

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SLIDE 10

Example 1

What is the change in gravitational potential energy when a 720-kg elevator moves from street level to the top of the Empire State building, 380 m above street level?

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SLIDE 11

Example 1 Solution

What is the change in gravitational potential energy when a 720-kg elevator moves from street level to the top of the Empire State building, 380 m above street level? ∆U = Uf − Ui = mgyf − mgyi = mg(yf − yi) ∆U = (720 kg)

  • 9.8 m/s2
  • (380 m) = 2.7 MJ

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SLIDE 12

Example 2

The spring in a spring gun has a force constant k = 700 N/m. It is compressed 3.0 cm from its natural length, and a 0.012-kg ball is put in the barrel against it. Assuming no friction and a horizontal gun barrel, with what speed will the ball leave the gun when released?

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SLIDE 13

Example 2 Solution

The spring in a spring gun has a force constant k = 700 N/m. It is compressed 3.0 cm from its natural length, and a 0.012-kg ball is put in the barrel against it. Assuming no friction and a horizontal gun barrel, with what speed will the ball leave the gun when released? Ki + Ui = Kf + Uf 0 + 1 2kx2 = 1 2mv2 + 0 v =

  • k

mx =

  • 700 N/m

0.012 kg (0.03 m) = 7.25 m/s

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SLIDE 14

Homework 12 - Due Fri. Oct. 8

  • Read Sections 7.1-7.2
  • Answer Questions 7.1 & 7.3
  • Do Problems 7.2, 7.5, & 7.9

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