2 Unit Bridging Course Day 1 More on Functions Collin Zheng 1 / - - PowerPoint PPT Presentation

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2 Unit Bridging Course Day 1 More on Functions Collin Zheng 1 / - - PowerPoint PPT Presentation

2 Unit Bridging Course Day 1 More on Functions Collin Zheng 1 / 37 Previously . . . In our introduction, we motivated the concept of functions with some intuitive and real-world examples. This included our drug function, which


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2 Unit Bridging Course – Day 1

More on Functions Collin Zheng

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Previously . . .

In our introduction, we motivated the concept of functions with some intuitive and real-world examples. This included our ‘drug function’, which calculated the dosage d of threadworm medication required for a person of weight w, defined precisely by the formula: d = f(w) = w 5 .

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Abstract functions

It’s important to realise that a function’s formula does not need to necessarily arise from real-world phenomena.

Example

For any number x, suppose we stipulate a purely mathematical rule where x is squared and 3 is then added. This gives rise to a function f(x) defined by the formula: f(x) = x2 + 3. This is an example of a quadratic function, which will be studied in more depth in days 3 and 4.

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SLIDE 4

Abstract functions

It’s important to realise that a function’s formula does not need to necessarily arise from real-world phenomena.

Example

For any number x, suppose we stipulate a purely mathematical rule where x is squared and 3 is then added. This gives rise to a function f(x) defined by the formula: f(x) = x2 + 3. This is an example of a quadratic function, which will be studied in more depth in days 3 and 4.

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SLIDE 5

Abstract functions

It’s important to realise that a function’s formula does not need to necessarily arise from real-world phenomena.

Example

For any number x, suppose we stipulate a purely mathematical rule where x is squared and 3 is then added. This gives rise to a function f(x) defined by the formula: f(x) = x2 + 3. This is an example of a quadratic function, which will be studied in more depth in days 3 and 4.

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SLIDE 6

Abstract functions

It’s important to realise that a function’s formula does not need to necessarily arise from real-world phenomena.

Example

For any number x, suppose we stipulate a purely mathematical rule where x is squared and 3 is then added. This gives rise to a function f(x) defined by the formula: f(x) = x2 + 3. This is an example of a quadratic function, which will be studied in more depth in days 3 and 4.

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Abstract functions (cont.)

Some example evaluations for f(x) = x2 + 3:

◮ f(4) = 42 + 3 = 19. ◮ f(−2) = (−2)2 + 3 = 7. ◮ f(x + h) = (x + h)2 + 3.

Practice Questions For practice, try evaluating the following:

◮ f(−5). ◮ f( a−b a2+b2+c2 ).

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SLIDE 8

Abstract functions (cont.)

Some example evaluations for f(x) = x2 + 3:

◮ f(4) = 42 + 3 = 19. ◮ f(−2) = (−2)2 + 3 = 7. ◮ f(x + h) = (x + h)2 + 3.

Practice Questions For practice, try evaluating the following:

◮ f(−5). ◮ f( a−b a2+b2+c2 ).

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SLIDE 9

Abstract functions (cont.)

Some example evaluations for f(x) = x2 + 3:

◮ f(4) = 42 + 3 = 19. ◮ f(−2) = (−2)2 + 3 = 7. ◮ f(x + h) = (x + h)2 + 3.

Practice Questions For practice, try evaluating the following:

◮ f(−5). ◮ f( a−b a2+b2+c2 ).

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SLIDE 10

Abstract functions (cont.)

Some example evaluations for f(x) = x2 + 3:

◮ f(4) = 42 + 3 = 19. ◮ f(−2) = (−2)2 + 3 = 7. ◮ f(x + h) = (x + h)2 + 3.

Practice Questions For practice, try evaluating the following:

◮ f(−5). ◮ f( a−b a2+b2+c2 ).

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SLIDE 11

Abstract functions (cont.)

Some example evaluations for f(x) = x2 + 3:

◮ f(4) = 42 + 3 = 19. ◮ f(−2) = (−2)2 + 3 = 7. ◮ f(x + h) = (x + h)2 + 3.

Practice Questions For practice, try evaluating the following:

◮ f(−5). ◮ f( a−b a2+b2+c2 ).

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SLIDE 12

Abstract functions (cont.)

Some example evaluations for f(x) = x2 + 3:

◮ f(4) = 42 + 3 = 19. ◮ f(−2) = (−2)2 + 3 = 7. ◮ f(x + h) = (x + h)2 + 3.

Practice Questions For practice, try evaluating the following:

◮ f(−5). ◮ f( a−b a2+b2+c2 ).

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SLIDE 13

Abstract functions (cont.)

Some example evaluations for f(x) = x2 + 3:

◮ f(4) = 42 + 3 = 19. ◮ f(−2) = (−2)2 + 3 = 7. ◮ f(x + h) = (x + h)2 + 3.

Practice Questions For practice, try evaluating the following:

◮ f(−5). ◮ f( a−b a2+b2+c2 ).

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SLIDE 14

Abstract functions (cont.)

Some example evaluations for f(x) = x2 + 3:

◮ f(4) = 42 + 3 = 19. ◮ f(−2) = (−2)2 + 3 = 7. ◮ f(x + h) = (x + h)2 + 3.

Practice Questions For practice, try evaluating the following:

◮ f(−5). ◮ f( a−b a2+b2+c2 ).

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SLIDE 15

Abstract functions (cont.)

Some example evaluations for f(x) = x2 + 3:

◮ f(4) = 42 + 3 = 19. ◮ f(−2) = (−2)2 + 3 = 7. ◮ f(x + h) = (x + h)2 + 3.

Practice Questions For practice, try evaluating the following:

◮ f(−5). ◮ f( a−b a2+b2+c2 ).

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SLIDE 16

Abstract functions (cont.)

Solutions As with the example evaluations above, the procedure is to simply replace x wherever it occurs in the formula f(x) = x2 + 3 with the input. Do not feel intimidated if the input is complicated – the procedure remains the same! Finally you should simplify your answer if possible.

◮ f(−5) = (−5)2 + 3 = 25 + 3 = 28. ◮ f( a−b a2+b2+c2 ) = ( a−b a2+b2+c2 )2 + 3.

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SLIDE 17

Abstract functions (cont.)

Solutions As with the example evaluations above, the procedure is to simply replace x wherever it occurs in the formula f(x) = x2 + 3 with the input. Do not feel intimidated if the input is complicated – the procedure remains the same! Finally you should simplify your answer if possible.

◮ f(−5) = (−5)2 + 3 = 25 + 3 = 28. ◮ f( a−b a2+b2+c2 ) = ( a−b a2+b2+c2 )2 + 3.

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SLIDE 18

Abstract functions (cont.)

Solutions As with the example evaluations above, the procedure is to simply replace x wherever it occurs in the formula f(x) = x2 + 3 with the input. Do not feel intimidated if the input is complicated – the procedure remains the same! Finally you should simplify your answer if possible.

◮ f(−5) = (−5)2 + 3 = 25 + 3 = 28. ◮ f( a−b a2+b2+c2 ) = ( a−b a2+b2+c2 )2 + 3.

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SLIDE 19

Abstract functions (cont.)

Solutions As with the example evaluations above, the procedure is to simply replace x wherever it occurs in the formula f(x) = x2 + 3 with the input. Do not feel intimidated if the input is complicated – the procedure remains the same! Finally you should simplify your answer if possible.

◮ f(−5) = (−5)2 + 3 = 25 + 3 = 28. ◮ f( a−b a2+b2+c2 ) = ( a−b a2+b2+c2 )2 + 3.

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SLIDE 20

Naming variables

It’s important to note that the x in f(x) = x2 + 3 is only a ‘dummy variable’ that symbolises the input for the function, whether it be a simple number or something very complicated like the

a−b a2+b2+c2 term above.

Thus, we certainly could have written the function as f(a) = a 2 + 3 or f(α) = α2 + 3. Although x is often preferred by convention, which letter or symbol one uses is ultimately

  • unimportant. That is, the x in f(x) = x2 + 3 is interchangeable.

So ultimately, f(x) = x2 + 3, f(a) = a 2 + 3 and f(α) = α2 + 3 are all the same functions!

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SLIDE 21

Naming variables

It’s important to note that the x in f(x) = x2 + 3 is only a ‘dummy variable’ that symbolises the input for the function, whether it be a simple number or something very complicated like the

a−b a2+b2+c2 term above.

Thus, we certainly could have written the function as f(a) = a 2 + 3 or f(α) = α2 + 3. Although x is often preferred by convention, which letter or symbol one uses is ultimately

  • unimportant. That is, the x in f(x) = x2 + 3 is interchangeable.

So ultimately, f(x) = x2 + 3, f(a) = a 2 + 3 and f(α) = α2 + 3 are all the same functions!

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SLIDE 22

Naming variables

It’s important to note that the x in f(x) = x2 + 3 is only a ‘dummy variable’ that symbolises the input for the function, whether it be a simple number or something very complicated like the

a−b a2+b2+c2 term above.

Thus, we certainly could have written the function as f(a) = a 2 + 3 or f(α) = α2 + 3. Although x is often preferred by convention, which letter or symbol one uses is ultimately

  • unimportant. That is, the x in f(x) = x2 + 3 is interchangeable.

So ultimately, f(x) = x2 + 3, f(a) = a 2 + 3 and f(α) = α2 + 3 are all the same functions!

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Naming functions

Suppose in a maths question you were asked to plot the graphs

  • f three different functions together on one xy-plane:

◮ y = 2x ◮ y = 1 ◮ y = x2 − 1

It would be unwise to name all three functions f(x), since any verbal or written reference to “the function f(x)” will only cause confusion, given that it’s the name given to all three functions!

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Naming functions

Suppose in a maths question you were asked to plot the graphs

  • f three different functions together on one xy-plane:

◮ y = 2x ◮ y = 1 ◮ y = x2 − 1

It would be unwise to name all three functions f(x), since any verbal or written reference to “the function f(x)” will only cause confusion, given that it’s the name given to all three functions!

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SLIDE 25

Naming functions

Suppose in a maths question you were asked to plot the graphs

  • f three different functions together on one xy-plane:

◮ y = 2x ◮ y = 1 ◮ y = x2 − 1

It would be unwise to name all three functions f(x), since any verbal or written reference to “the function f(x)” will only cause confusion, given that it’s the name given to all three functions!

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Naming functions

The convention used to overcome this problem is to rename the f in f(x). For instance, we can name:

◮ y = 2x

as f (x) = 2x

◮ y = 1

as g (x) = 1

◮ y = x2 − 1

as h (x) = x2 − 1 Under this tradition, the f in y = f(x) no longer just means that y is a function of x, but also as a name for the function itself. This convention is ubiquitous throughout maths, providing us the capability to assign distinct names to different functions whenever they are to be considered under the same setting.

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SLIDE 27

Naming functions

The convention used to overcome this problem is to rename the f in f(x). For instance, we can name:

◮ y = 2x

as f (x) = 2x

◮ y = 1

as g (x) = 1

◮ y = x2 − 1

as h (x) = x2 − 1 Under this tradition, the f in y = f(x) no longer just means that y is a function of x, but also as a name for the function itself. This convention is ubiquitous throughout maths, providing us the capability to assign distinct names to different functions whenever they are to be considered under the same setting.

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Naming functions

The convention used to overcome this problem is to rename the f in f(x). For instance, we can name:

◮ y = 2x

as f (x) = 2x

◮ y = 1

as g (x) = 1

◮ y = x2 − 1

as h (x) = x2 − 1 Under this tradition, the f in y = f(x) no longer just means that y is a function of x, but also as a name for the function itself. This convention is ubiquitous throughout maths, providing us the capability to assign distinct names to different functions whenever they are to be considered under the same setting.

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SLIDE 29

Naming functions

The convention used to overcome this problem is to rename the f in f(x). For instance, we can name:

◮ y = 2x

as f (x) = 2x

◮ y = 1

as g (x) = 1

◮ y = x2 − 1

as h (x) = x2 − 1 Under this tradition, the f in y = f(x) no longer just means that y is a function of x, but also as a name for the function itself. This convention is ubiquitous throughout maths, providing us the capability to assign distinct names to different functions whenever they are to be considered under the same setting.

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Naming functions

Let’s now try to sketch the functions f, g and h together on the same plane. Firstly, here’s the graph of f(x) = 2x: x f(x)

  • 2
  • 1

1 2

  • 1

1 2 3 f(x) = 2x

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Naming functions

Let’s now try to sketch the functions f, g and h together on the same plane. Firstly, here’s the graph of f(x) = 2x: x f(x)

  • 2
  • 1

1 2

  • 1

1 2 3 f(x) = 2x

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Naming functions

Here’s the graph of g(x) = 1: x g(x) 1 g(x) = 1 f(x) and g(x) are examples of linear functions, which will be studied in more depth in Day 2.

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Naming functions

Finally, here’s the graph of h(x) = x2 − 1, an example of a quadratic function. x h(x)

r

(−2, 3)

r

(−1, 0)

r

(0, −1)

r

h (x) = x2 − 1 (1, 0)

r

(2, 3) We’ll look at quadratic functions in more detail in Day 3.

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Naming functions

Finally, plotting all three functions together on the same graph: x y h (x) = x2 − 1 g(x) = 1 f(x) = 2x

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Summary

◮ Functions may arise naturally from real-world phenomena

  • r they may be defined by abstract mathematical formulas.

◮ The x in f(x) is an interchangeable symbol used to

represent the independent variable, while the f in f(x) is

  • ften used to denote the name of the function.

◮ A wide range of different classes of functions will be

studied throughout this bridging course: – Linear (Day 2) – Quadratic (Days 3-4) – General polynomials (Days 5-6) – Exponential (Day 8) – Circular (Day 10) – Logarithmic (Day 11)

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SLIDE 36

Summary

◮ Functions may arise naturally from real-world phenomena

  • r they may be defined by abstract mathematical formulas.

◮ The x in f(x) is an interchangeable symbol used to

represent the independent variable, while the f in f(x) is

  • ften used to denote the name of the function.

◮ A wide range of different classes of functions will be

studied throughout this bridging course: – Linear (Day 2) – Quadratic (Days 3-4) – General polynomials (Days 5-6) – Exponential (Day 8) – Circular (Day 10) – Logarithmic (Day 11)

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Summary

◮ Functions may arise naturally from real-world phenomena

  • r they may be defined by abstract mathematical formulas.

◮ The x in f(x) is an interchangeable symbol used to

represent the independent variable, while the f in f(x) is

  • ften used to denote the name of the function.

◮ A wide range of different classes of functions will be

studied throughout this bridging course: – Linear (Day 2) – Quadratic (Days 3-4) – General polynomials (Days 5-6) – Exponential (Day 8) – Circular (Day 10) – Logarithmic (Day 11)

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