Signal Circuit and Transistor Small-Signal Model
Lecture notes: Sec. 5 Sedra & Smith (6th Ed): Sec. 5.5 & 6.7 Sedra & Smith (5th Ed): Sec. 4.6 & 5.6
- F. Najmabadi, ECE65, Winter 2012
Signal Circuit and Transistor Small-Signal Model Lecture notes: - - PowerPoint PPT Presentation
Signal Circuit and Transistor Small-Signal Model Lecture notes: Sec. 5 Sedra & Smith (6 th Ed): Sec. 5.5 & 6.7 Sedra & Smith (5 th Ed): Sec. 4.6 & 5.6 F. Najmabadi, ECE65, Winter 2012 Transistor Amplifier Development Bias &
..... : ,...) ( , , , : MOS
r R R r R R D gs GS GS D DS GS
i I i v V v R v V v i v v + = + = + = ..... , : , , , : MOS
R R D D DS GS
I V R I V V ..... , : , , , : MOS
r r D d ds gs
i v R i v v
R R R R R R r
r r
C C C C C C c
c c =
S S IVS IVS ivs
ivs ivs
Exercise: Show that dependent sources remain as dependent sources
− × = − + = − = 1 exp exp exp exp : Signal
T d T D s d T D s T d D s D D d
nV v nV V I i nV V I nV v V I I i i
VD ID vd id ?
= +
T D s D
nV v I i exp : Signal Bias =
T D s D
nV V I I exp : Bias
vD iD
1 exp − × =
T d D d
nV v I i
1 exp − × =
T d D d
nV v I i
vd id ?
D T D T d D d T d T d T d T d T d T d
v nV I nV v I i nV v nV v nV v nV v nV v nV v = − + × ≈ + ≈ << + + + = 1 1 1 exp : 1 If .... ! 2 1 1 exp : Exapnsion Series Taylor
2 d d d D T d
i r i I nV v = =
2 ) 2 ( ) 1 (
a A a A
) 2 ( ) 1 ( A A a
a A a a
) 1 (
a A A a A a A A A A A A A A A A A
) 1 ( 2 ) 2 ( ) 1 ( 2 ) 2 ( ) 1 (
a A A A a A
) 1 (
D nV v S D
T D
T T
nV v S T nV v S
) 1 (
S nV V S nV V S D D
I e I e I V f I
T D T D
− = − ⋅ = =
d T S D d T nV V S d V v T nV v S d D d
v nV I I v nV e I v nV e I v V f i
T D D T
× + = × ⋅ = × ⋅ = × =
=
) (
) 1 ( d T D d T S D d
v nV I v nV I I i × ≈ × + =
d d d
D T d
vd id rd = nVT/ID vD iD
D T D d d D d
) 1 ( ) 1 (
ds V V DS gs V V GS D DS DS V V DS GS GS V V GS DS GS DS GS D d D
v v f v v f I V v v f V v v f V V f v v f i i I
DS GS DS GS DS GS DS GS
× ∂ ∂ + × ∂ ∂ + ≈ + − ⋅ ∂ ∂ + − ⋅ ∂ ∂ + = = = +
, , , ,
... ) ( ) ( ) , ( ) , (
, , ds V V DS gs V V GS d
DS GS DS GS
ds V V DS gs V V GS d
v v f v v f i
DS GS DS GS
⋅ ∂ ∂ + ⋅ ∂ ∂ =
, ,
) , ( ) 1 ( ) ( 5 .
2 DS GS DS t GS
n D
v v f v V v L W C i = + − = λ µ
m OV D t GS DS t GS
n V V DS t GS
n V V GS
g V I V V V V V L W C v V v L W C v f
DS GS DS GS
≡ = − + − × = + − × = ∂ ∂ 2 ) ( ) 1 ( ) ( 5 . 2 ) 1 )( ( 5 . 2
2 , ,
λ µ λ µ
DS D DS DS t GS
n V V t GS
n V V DS
r I V I V V V V L W C V v L W C v f
DS GS DS GS
1 ) 1 ( ) 1 ( ) 1 ( ) ( 5 . ) ( 5 .
2 , 2 ,
≡ ≈ + = + + − × = − × = ∂ ∂ λ λ λ λ λ µ λ µ λ = + ⋅ =
g
gs m d
gs m d g
D
OV D m
OV A OV
+ = =
A CE V v s C V v s B
V v e I i e I i
T BE T BE
1 ) / ( β We need to perform Taylor Series Expansion in 2 variables for both iB and iC.
, 1 be V V BE B
CE BE
, 2 , 2 ce V V DCE be V V BE C
CE BE CE BE
be m c be b
π
) ( ) / (
1 BE V v s B
v f e I i
T BE
= = β
be be V V BE B
CE BE
π
, 1 π
T B V V v s T V V BE
BE T BE CE BE
, 1
T BE
V V s B
e I I ) / ( β = + =
A CE V v s C
V v e I i
T BE
1
A CE A V V s A CE V V s C
V V V e I V V e I I
T BE T BE
+ × = + = 1
m T C V A CE V v T s V V BE
CE V BE T BE CE BE
,
, 2
A C V V v A s V V CE
CE V BE T BE CE BE
,
, 2
C A C CE A
T C m
be m c be b
π B T
π
π π π π π
m T B B C T C m
D
D m
C A
C m B T
π π