SLIDE 28 analytical solutions
δ = 3(1 + w)2 3c2
s(1 + w) + 8 (c2 s − w) c2 v
φ0 k2 V = −3aH
s − w
σ = − 8c2
v
s − w
s(1 + w) + 8(c2 s − w)c2 v
φ0 k2 Remind that aH = H0 √ Ωma−1/2 kc2
v ∼ aH
σ′ = −3 aσ + 8 3 c2
v
(1 + w)2 V a2H effective sound speed: c2
eff = c2 s + 8
3 (c2
s − w)
(1 + w) c2
v
105 104 0.001 0.01 0.1 1 0.01 0.1 1 10 100 a ∆DE DE sub
numerical solution with k = 200H0 for different values of c2
v:
c2
v = 10−1, 10−2, 10−3, 10−4 and 10−5
vertical lines: a at which each mode enters the anisotropic horizon c2
s = 10−2
radiation omitted for visualisation purposes Elisabetta Majerotto (UAM) “What is ν?” workshop at GGI Florence - 15/06/2012 7 / 13